DisplayData [Integer (one-dimensional array)]

Function

Sets the data to be drawn on the graph with an integer value of a one-dimensional array.

Format

Ret = dncGraph1.DisplayData(Data)

Parameters

Data [ C#: int[] ] [ VB.NET: Integer() ]

Specifies the graph data. Specify the data as an integer value in a one-dimensional array.

Return value

Ret [ C#: int ] [ VB.NET: Integer ]

Value	Description
0	Normality completion
510001	The input parameter is invalid. Check the parameter contents.

Other errors (see: Error code details)

Remarks

The data to be drawn are stored as integer value in a one-dimensional array.

According to the number of lines and the number of Y-axis data to be drawn,
the data from the first channel to the last channel are stored as a set.

[Stored image]
Draw 3 lines for 2 Y-axis data
[Line0[data0], Line1[data0], Line2[data0], Line0[data1], Line1[data1], Line2[data1]]

The graph is drawn in a format that the data are inserted in order to the left end of the Y axis.

Example

Line No.0 data 0, 100, 200
Line No.1 data 100, 200, 300
Line No.2 data 200, 300, 400

Draw a graph with the above data.

int Ret
int[] Data = new int[9];
short line_no, data_no;

for(data_no = 0; data_no < 3; data_no++){
  for(line_no = 0; line_no < 3; line_no++){
      Data[(data_no * 3) +line_no] = (line_no + data_no) * 100;
  }
}

Ret = dncGraph1.DisplayData(Data);

VB.NET

Dim Ret As Integer
Dim Data(8) As Integer
Dim line_no As Short
Dim data_no As Short

For data_no = 0 To 2
  For line_no = 0 To 2
      Data((data_no * 3) + line_no)) = (line_no + data_no) * 100
  Next line_no
Next data_no

Ret = dncGraph1.DisplayData(Data)