DiInputMultiBit

Function

 

Inputs multiple bits from digital input bits.

 

Format

 

ret = dncDaq01.DiInputMultiBit(DeviceNo, DiBit, DiBitNum, DiData)

 

Parameters

 

DeviceNo [ C#: short ] [ VB.NET: Short ]

Specifies the device No. managed by DncDaq.

 

DiBit [ C#: out short ] [ VB.NET: Short ]

Stores the logical input bit numbers into an array, and specify the base address of this array.
The logical input bit number is a number, which is assigned from the first input bit of a device as 0 to the last one consecutively.

 

DiBitNum [ C#: short ] [ VB.NET: Short ]

Specifies the number of bits which are specified by BitNo. The maximum number of bits is 256.

 

DiData [ C#: out byte ] [ VB.NET: Byte ]  

Specifies the address of the variable that stores the input data.

 

Return value

 

Ret [ C#: int ] [ VB.NET: Integer ]

 

■Common

Value

Description

0

Normality completion

500001

The method on an unconfigured device has been called. Check the device settings.

500002

The method was called that the device does not support.

510001

The input parameter is invalid. Check the parameter contents.

 

■DIO Devices

Value

Description

10100

Invalid data buffer address.

20102

The bit number exceeds the specifiable range.

20103

Bit number beyond the limit.

Other errors (see: Error code details)

 

Remarks

 

Inputs multiple bits from input bits. Before this function is called, it is necessary that the logical bit numbers to be input are set into the array specified by DiBit.
The input data are stored into the array named DiData by the order of logical bits which are specified by DiBit.

 

Example

 

Inputs data from bit 0 and bit 1.

C#

int     Ret
short[] DiBit  = new short[2];
byte[]  DiData = new byte[2];

DiBit[0] = 0;
DiBit[1] = 1;
Ret = dncDaq01.DiInputMultiBit(DeviceNo, DiBit, 2, DiData);

 

VB.NET

Dim Ret As Integer
Dim DiBit(1) As Short
Dim DiData(1) As Byte

Ret = dncDaq01.DiInputMultiBit(DeviceNo, DiBit, 2, DiData)